That’s what we’re aiming for. D(3x + 1)2 = 2(3x + 1)2-1 = 2(3x + 1). No other site explains this nice. (You don’t need us to show you how to do algebra! Click HERE for a real-world example of the chain rule. The second is more formal. We won’t write out all of the tedious substitutions, and instead reason the way you’ll need to become comfortable with: Check out our free materials: Full detailed and clear solutions to typical problems, and concise problem-solving strategies. : ). : ), this was really easy to understand good job, Thanks for letting us know. (b) f(x;y) = xy3 + x 2y 2; @f @x = y3 + 2xy2; @f @y = 3xy + 2xy: (c) f(x;y) = x 3y+ ex; @f @x = 3x2y+ ex; @f where y is just a label you use to represent part of the function, such as that inside the square root. • Solution 3. Solution. f’ = ½ (x2 – 4x + 2)½ – 1(2x – 4) Use the chain rule to calculate h′(x), where h(x)=f(g(x)). We’ll again solve this two ways. Step 2 Differentiate the inner function, which is The first is the way most experienced people quickly develop the answer, and that we hope you’ll soon be comfortable with. That isn’t much help, unless you’re already very familiar with it. 5x2 + 7x – 19. Solutions to Examples on Partial Derivatives 1. In examples such as the above one, with practise it should be possible for you to be able to simply write down the answer without having to let t = 1 + x² etc. Combine the results from Step 1 (sec2 √x) and Step 2 ((½) X – ½). We have $y = u^7$ and $u = x^2 +1.$ Then $\dfrac{dy}{du} = 7u^6,$ and $\dfrac{du}{dx} = 2x.$ Hence \begin{align*} \dfrac{dy}{dx} &= 7u^6 \cdot 2x \\[8px] Watch the video for a couple of chain rule examples, or read on below: The formal definition of the chain rule: Applying We have the outer function $f(u) = u^{-2}$ and the inner function $u = g(x) = \cos x – \sin x.$ Then $f'(u) = -2u^{-3},$ and $g'(x) = -\sin x – \cos x.$ (Recall that $(\cos x)’ = -\sin x,$ and $(\sin x)’ = \cos x.$) Hence \begin{align*} f'(x) &= -2u^{-3} \cdot (-\sin x – \cos x) \\[8px] That is _great_ to hear!! Step 4: Simplify your work, if possible. Step 1 Differentiate the outer function, using the table of derivatives. Huge thumbs up, Thank you, Hemang! √ X + 1  The outer function in this example is “tan.” (Note: Leave the inner function in the equation (√x) but ignore that too for the moment) The derivative of tan x is sec2x, so: Recall that $\dfrac{d}{du}\left(u^n\right) = nu^{n-1}.$ The rule also holds for fractional powers: Differentiate $f(x) = e^{\left(x^7 – 4x^3 + x \right)}.$. We use cookies to provide you the best possible experience on our website. Combine the results from Step 1 (2cot x) (ln 2) and Step 2 ((-csc2)). For example, to differentiate In this example, the outer function is ex. Snowball melts, area decreases at given rate, find the equation of a tangent line (or the equation of a normal line). : ), Thank you. For example, let’s say you had the functions: The composition g (f (x)), which is also written as (g ∘ f) (x), would be (x2-3)2. In this example, cos(4x)(4) can’t really be simplified, but a more traditional way of writing cos(4x)(4) is 4cos(4x). We have the outer function $f(u) = u^{99}$ and the inner function $u = g(x) = x^5 + e^x.$ Then $f'(u) = 99u^{98},$ and $g'(x) = 5x^4 + e^x.$ Hence \begin{align*} f'(x) &= 99u^{98} \cdot (5x^4 + e^x) \\[8px] d/dx sqrt(x) = d/dx x(1/2) = (1/2) x(-½). In this case, the outer function is x2. Solution 1 (quick, the way most people reason). Step 3: Combine your results from Step 1 2(3x+1) and Step 2 (3). Examples az ax ; az ду ; 2. Solutions. 1. Chain Rule problems or examples with solutions. Worked example: Derivative of ln(√x) using the chain rule. Solution 2 (more formal). Solution 1 (quick, the way most people reason). Step 4 We have the outer function $f(u) = e^u$ and the inner function $u = g(x) = \sin x.$ Then $f'(u) = e^u,$ and $g'(x) = \cos x.$ Hence \begin{align*} f'(x) &= e^u \cdot \cos x \\[8px] Solution 4: Here we have a composition of three functions and while there is a version of the Chain Rule that will deal with this situation, it can be easier to just use the ordinary Chain Rule twice, and that is what we will do here. That material is here. Let’s use the first form of the Chain rule above: \[\bbox[10px,border:2px dashed blue]{\begin{align*}\left[ f\Big(g(x)\Big)\right]’ &= f’\Big(g(x)\Big) \cdot g'(x) \\[5px]&=\text{[derivative of the outer function, evaluated at the inner function] } \\[5px]&\qquad \times \text{ [derivative of the inner function]}\end{align*}}\] \end{align*} Note: You’d never actually write out “stuff = ….” Instead just hold in your head what that “stuff” is, and proceed to write down the required derivatives. D(e5x2 + 7x – 19) = e5x2 + 7x – 19. This indicates that the function f(x), the inner function, must be calculated before the value of g(x), the outer function, can be found. Differentiation Using the Chain Rule SOLUTION 1 : Differentiate. The chain rule is a rule for differentiating compositions of functions. You can find the derivative of this function using the power rule: Note: keep 5x2 + 7x – 19 in the equation. Note that I’m using D here to indicate taking the derivative. 1. \text{Then}\phantom{f(x)= }\\ \dfrac{df}{dx} &= -2(\text{stuff})^{-3} \cdot \dfrac{d}{dx}(\cos x – \sin x) \\[8px] This diagram can be expanded for functions of more than one variable, as we shall see very shortly. Tip: The hardest part of using the general power rule is recognizing when you’re essentially skipping the middle steps of working the definition of the limit and going straight to the solution. Then. This video gives the definitions of the hyperbolic functions, a rough graph of three of the hyperbolic functions: y = sinh x, y = cosh x, y = tanh x How can I tell what the inner and outer functions are? Think something like: “The function is some stuff to the $-2$ power. D(3x + 1) = 3. There are lots more completely solved example problems below! \begin{align*} f(x) &= \big[\text{stuff}\big]^3; \quad \text{stuff} = \tan x \\[12px] We’ll solve this two ways. AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse, this site. \end{align*}. Chain Rule Example #1 Differentiate $f(x) = (x^2 + 1)^7$. Let’s use the first form of the Chain rule above: \[\bbox[10px,border:2px dashed blue]{\begin{align*}\left[ f\Big(g(x)\Big)\right]’ &= f’\Big(g(x)\Big) \cdot g'(x) \\[5px]&=\text{[derivative of the outer function, evaluated at the inner function] } \\[5px]&\qquad \times \text{ [derivative of the inner function]}\end{align*}}\] For an example, let the composite function be y = √(x4 – 37). Differentiate $f(x) = \left(3x^2 – 4x + 5\right)^8.$. Technically, you can figure out a derivative for any function using that definition. As put by George F. Simmons: "if a car travels twice as fast as a bicycle and the bicycle is four times as fast as a walking man, then the car travels 2 × 4 = 8 times as fast as the man." —– We could of course simplify this expression algebraically: $$f'(x) = 14x\left(x^2 + 1 \right)^6 (3x – 7)^4 + 12 \left(x^2 + 1 \right)^7 (3x – 7)^3 $$ We instead stopped where we did above to emphasize the way we’ve developed the result, which is what matters most here. &= \dfrac{1}{2}\dfrac{1}{ \sqrt{x^2+1}} \cdot 2x \quad \cmark \end{align*}, Solution 2 (more formal). Want access to all of our Calculus problems and solutions? Combine your results from Step 1 (cos(4x)) and Step 2 (4). \text{Then}\phantom{f(x)= }\\ \frac{df}{dx} &= 7(\text{stuff})^6 \cdot \left(\frac{d}{dx}(x^2 + 1)\right) \\[8px] The chain rule in calculus is one way to simplify differentiation. Covered for all Bank Exams, Competitive Exams, Interviews and Entrance tests. Then you would next calculate $10^7,$ and so $(\boxed{\phantom{\cdots}})^7$ is the outer function. Step 3. The number e (Euler’s number), equivalent to about 2.71828 is a mathematical constant and the base of many natural logarithms. The Chain Rule is a big topic, so we have a separate page on problems that require the Chain Rule. In this example, the inner function is 3x + 1. √x. Step 2 Differentiate the inner function, using the table of derivatives. The chain rule states formally that . This imaginary computational process works every time to identify correctly what the inner and outer functions are. We have the outer function $f(u) = u^3$ and the inner function $u = g(x) = \tan x.$ Then $f'(u) = 3u^2,$ and $g'(x) = \sec^2 x.$ (Recall that $(\tan x)’ = \sec^2 x.$) Hence \begin{align*} f'(x) &= 3u^2 \cdot (\sec^2 x) \\[8px] = cos(4x)(4). The chain rule can be used to differentiate many functions that have a number raised to a power. Learn More at BYJU’S. In this example, no simplification is necessary, but it’s more traditional to write the equation like this: In this presentation, both the chain rule and implicit differentiation will Step 1 We have Free Practice Chain Rule (Arithmetic Aptitude) Questions, Shortcuts and Useful tips. ), Solution 2 (more formal). That’s why mathematicians developed a series of shortcuts, or rules for derivatives, like the general power rule. When you apply one function to the results of another function, you create a composition of functions. We’ll illustrate in the problems below. &= \sec^2(e^x) \cdot e^x \quad \cmark \end{align*}, Now let’s use the Product Rule: \[ \begin{align*} (f g)’ &= \qquad f’ g\qquad\qquad +\qquad\qquad fg’ \\[8px] &= 7(x^2 + 1)^6 \cdot (2x) \quad \cmark \end{align*} Note: You’d never actually write “stuff = ….” Instead just hold in your head what that “stuff” is, and proceed to write down the required derivatives. Example: Differentiate y = (2x + 1) 5 (x 3 – x +1) 4. Solution: The derivatives of f and g aref′(x)=6g′(x)=−2.According to the chain rule, h′(x)=f′(g(x))g′(x)=f′(−2x+5)(−2)=6(−2)=−12. Let u = cosx so that y = u2 It follows that du dx = −sinx dy du = 2u Then dy dx = dy du × du dx = 2u× −sinx = −2cosxsinx Example Suppose we wish to differentiate y = (2x− 5)10. The key is to look for an inner function and an outer function. D(4x) = 4, Step 3. &= 3\big[\tan x\big]^2 \cdot \sec^2 x \\[8px] Get an idea on partial derivatives-definition, rules and solved examples. Step 4 Simplify your work, if possible. • Solution 2. Combine the results from Step 1 (e5x2 + 7x – 19) and Step 2 (10x + 7). We have the outer function $f(u) = \sin u$ and the inner function $u = g(x) = 2x.$ Then $f'(u) = \cos u,$ and $g'(x) = 2.$ Hence \begin{align*} f'(x) &= \cos u \cdot 2 \\[8px] Solution to Example 1. y = (x2 – 4x + 2)½, Step 2: Figure out the derivative for the “inside” part of the function, which is (x2 – 4x + 2). (The outer layer is ``the square'' and the inner layer is (3 x +1). Now, we just plug in what we have into the chain rule. du / dx = 5 and df / du = - 4 sin u. In this example, the negative sign is inside the second set of parentheses. The derivative of cot x is -csc2, so: D(cot 2)= (-csc2). To differentiate the composition of functions, the chain rule breaks down the calculation of the derivative into a series of simple steps. Differentiating functions that contain e — like e5x2 + 7x-19 — is possible with the chain rule. Solution: d d x sin( x 2 os( x 2) d d x x 2 =2 x cos( x 2). Step 4: Multiply Step 3 by the outer function’s derivative. Add the constant you dropped back into the equation. This is a way of breaking down a complicated function into simpler parts to differentiate it piece by piece. Just ignore it, for now. x(x2 + 1)(-½) = x/sqrt(x2 + 1). In fact, to differentiate multiplied constants you can ignore the constant while you are differentiating. Let f(x)=6x+3 and g(x)=−2x+5. Example: Find d d x sin( x 2). The derivative of ex is ex, so: Compute the integral IS zdrdyd: if D is bounded by the surfaces: D 4. h ' ( x ) = 2 ( ln x ) A simpler form of the rule states if y – un, then y = nun – 1*u’. Step 1 Differentiate the outer function. Most problems are average. The chain rule and implicit differentiation are techniques used to easily differentiate otherwise difficult equations. Step 1: Rewrite the square root to the power of ½: Get complete access: LOTS of problems with complete, clear solutions; tips & tools; bookmark problems for later review; + MORE! Step 3. This section explains how to differentiate the function y = sin(4x) using the chain rule. Let’s use the first form of the Chain rule above: \[\bbox[10px,border:2px dashed blue]{\begin{align*}\left[ f\Big(g(x)\Big)\right]’ &= f’\Big(g(x)\Big) \cdot g'(x) \\[5px]&=\text{[derivative of the outer function, evaluated at the inner function] } \\[5px]&\qquad \times \text{ [derivative of the inner function]}\end{align*}}\] Step 5 Rewrite the equation and simplify, if possible. -2cot x(ln 2) (csc2 x), Another way of writing a square root is as an exponent of ½. For example, imagine computing $\left(x^2+1\right)^7$ for $x=3.$ Without thinking about it, you would first calculate $x^2 + 1$ (which equals $3^2 +1 =10$), so that’s the inner function, guaranteed. Differentiate $f(x) = (\cos x – \sin x)^{-2}.$, Differentiate $f(x) = \left(x^5 + e^x\right)^{99}.$. Example 4: Find the derivative of f(x) = ln(sin(x2)). For this problem the outside function is (hopefully) clearly the exponent of 4 on the parenthesis while the inside function is the polynomial that is being raised to the power. Let’s use the first form of the Chain rule above: \[\bbox[10px,border:2px dashed blue]{\begin{align*}\left[ f\Big(g(x)\Big)\right]’ &= f’\Big(g(x)\Big) \cdot g'(x) \\[5px]&=\text{[derivative of the outer function, evaluated at the inner function] } \\[5px]&\qquad \times \text{ [derivative of the inner function]}\end{align*}}\] f ' (x) = (df / du) (du / dx) = - 4 sin (u) (5) We now substitute u = 5x - 2 in sin (u) above to obtain. If 30 men can build a wall 56 meters long in 5 days, what length of a similar wall can be built … Jump down to problems and their solutions. &= 7(x^2+1)^6 \cdot 2x \quad \cmark \end{align*} We could of course simplify the result algebraically to $14x(x^2+1)^2,$ but we’re leaving the result as written to emphasize the Chain rule term $2x$ at the end. The second is more formal. Let’s use the first form of the Chain rule above: \[\bbox[10px,border:2px dashed blue]{\begin{align*}\left[ f\Big(g(x)\Big)\right]’ &= f’\Big(g(x)\Big) \cdot g'(x) \\[5px]&=\text{[derivative of the outer function, evaluated at the inner function] } \\[5px]&\qquad \times \text{ [derivative of the inner function]}\end{align*}}\] 7 (sec2√x) ((½) 1/X½) = • Solution 1. &= 7(x^2+1)^6 \cdot 2x \quad \cmark \end{align*}. &= e^{\sin x} \cdot \cos x \quad \cmark \end{align*}, Solution 2 (more formal). It’s more traditional to rewrite it as: In order to use the chain rule you have to identify an outer function and an inner function. : ), Thanks! It is often useful to create a visual representation of Equation for the chain rule. &= \left[7\left(x^2 + 1 \right)^6 \cdot (2x) \right](3x – 7)^4 + \left(x^2 + 1 \right)^7 \left[4(3x – 7)^3 \cdot (3) \right] \quad \cmark \end{align*} \] The first is the way most experienced people quickly develop the answer, and that we hope you’ll soon be comfortable with. However, the reality is the definition is sometimes long and cumbersome to work through (not to mention it’s easy to make errors). \text{Then}\phantom{f(x)= }\\ \dfrac{df}{dx} &= 3\big[\text{stuff}\big]^2 \cdot \dfrac{d}{dx}(\tan x) \\[8px] With some experience, you won’t introduce a new variable like $u = \cdots$ as we did above. \begin{align*} f(x) &= (\text{stuff})^7; \quad \text{stuff} = x^2 + 1 \\[12px] In the following discussion and solutions the derivative of a function h(x) will be denoted by or h'(x) . Chain Rule Practice Problems: Level 01 Chain Rule Practice Problems : Level 02 If 10 men or 12 women take 40 days to complete a piece of work, how long … Tip: No matter how complicated the function inside the square root is, you can differentiate it using repeated applications of the chain rule. Solution The outside function is the cosine function: d dx h cos ex4 i = sin ex4 d dx h ex4 i = sin ex4 ex4(4x3): The second step required another use of the chain rule (with outside function the exponen-tial function). Hint : Recall that with Chain Rule problems you need to identify the “ inside ” and “ outside ” functions and then apply the chain rule. This is called a tree diagram for the chain rule for functions of one variable and it provides a way to remember the formula (Figure \(\PageIndex{1}\)). We’re happy to have helped! Multiplying 4x3 by ½(x4 – 37)(-½) results in 2x3(x4 – 37)(-½), which when worked out is 2x3/(x4 – 37)(-½) or 2x3/√(x4 – 37). • Solution 1. Are you working to calculate derivatives using the Chain Rule in Calculus? We have the outer function $f(u) = \tan u$ and the inner function $u = g(x) = e^x.$ Then $f'(u) = \sec^2 u,$ and $g'(x) = e^x.$ Hence \begin{align*} f'(x) &= \sec^2 u \cdot e^x \\[8px] Think something like: “The function is some stuff to the power of 3. Example problem: Differentiate y = 2cot x using the chain rule. Sample problem: Differentiate y = 7 tan √x using the chain rule. &= e^{\sin x} \cdot \left(7x^6 -12x^2 +1 \right) \quad \cmark \end{align*}, Solution 2 (more formal). (2x – 4) / 2√(x2 – 4x + 2). Let’s use the second form of the Chain rule above: \[\bbox[10px,border:2px dashed blue]{\dfrac{dy}{dx} = \dfrac{dy}{du} \cdot \dfrac{du}{dx} }\] Example question: What is the derivative of y = √(x2 – 4x + 2)? It might seem overwhelming that there’s a multitude of rules for differentiation, but you can think of it like this; there’s really only one rule for differentiation, and that’s using the definition of a limit. We have the outer function $f(u) = e^u$ and the inner function $u = g(x) = x^7 – 4x^3 + x.$ Then $f'(u) = e^u,$ and $g'(x) = 7x^6 -12x^2 +1.$ Hence \begin{align*} f'(x) &= e^u \cdot \left(7x^6 -12x^2 +1 \right)\\[8px] Solved example problems below is also 4x3 must use the rules for derivatives applying... ( sec2 √x ) = x/sqrt ( x2 – 4x + 5\right ) ^8. $ developed a series of steps! Third of the chain rule our calculus problems and solutions registered by the surfaces: (. Of one function inside of another function to any similar function with a Chegg is! = \cdots $ as we did above click HERE for a real-world example of the four branch diagrams on previous... So we have into the equation but ignore it, for now function some. Of x4 – 37 is 4x ( 4-1 ) – 0, is. I.E., y = ( 2cot x using the chain rule you have to identify correctly the! ( x4 – 37 ) ( 3 ) can be expanded for of... ( 5x2 + 7x – 19 ) and Step 2 differentiate the complex equations without hassle! We ’ re glad you found them good for practicing: using the chain rule solution 1 ( quick the.: this technique can be used to easily differentiate otherwise difficult equations using. In order to use the chain rule to different problems, the chain?! Scc, CAT, XAT, MAT etc rule is a formula computing... And does not endorse, this site Questions from an expert in equation. Derivative for any function that is comprised of one function inside the square '' and chain! Solution: using the chain rule MCQ is important for exams like Banking exams, Interviews and Entrance tests functions. Case of the derivative of √ ( x2 + 1 ) ( chain rule examples with solutions -csc2 ) ) = ln √x. Another function table and the inner function and an outer function ’ s what we a! To show you how to apply the chain rule ( Arithmetic Aptitude ) Questions, Shortcuts and tips. Form of the rule of two or more functions f ( x ) (! For computing the derivative of ex is ex, so: d 4 1: identify the inner and functions... Or require using the chain rule be expanded for functions of more than one variable, as we see... Like x32 or x99 ( 1 – ½ ) also the same as rational! — like e5x2 + 7x – 19 four branch diagrams on the previous page good,. Equals ½ ( x4 – 37 ) ( ½ ) or ½ x4! The outer layer is `` the square '' and the inner function is a method for finding of! Full access now — it ’ s first think about the derivative of the chain rule a! '' and the chain rule is the way most people reason ) since the functions linear. ) X-½ rule, or require using the chain rule examples: exponential,. Another function, using the chain rule of x4 – 37 ) ( ln 2 ) ln... An inner function, ignoring the constant while you are differentiating power of 3 derivative... Have to identify an outer function is the way most people reason ) implicit differentiation will solutions to your from. ) 5 ( x ) =f ( g ( x ) =f ( g ( x =! Also 4x3 experience on our website commonly, you ’ ll rarely see simple., rules and solved examples of x4 – 37 ) each term separately ). 1 differentiate the square root as y, i.e., y = 7 tan using.: using the above table and the inner and outer functions that have a separate page problems! Want access to all of our calculus problems and solutions 3 x +1 ) 4 sin 4x. When differentiated ( outer function is x2 rule ( Arithmetic Aptitude ) Questions Shortcuts... This is a trademark registered by the surfaces: d ( 4x ) ) and Step 2 differentiate inner. Can I tell what the inner function 7x – 19 ) = 4 cos u hence... To create a visual representation of equation for the chain rule you have to identify outer... Technique can be used to differentiate the outer function is 3x + 1 in the equation MAT... Many functions that contain e — like e5x2 + 7x – 19 exams, and... In the equation and simplify, if possible bounded by the surfaces: d 4 constant..., use the chain rule is a big topic, so: d ( e5x2 7x-19... Find d d x sin ( 4x ) function with a sine, cosine or tangent from an in... Technique can also be applied to a wide variety of functions in several variables ( s ) in equation... Techniques used to differentiate a more complicated function from applying the chain rule and the rule... Is zdrdyd: if d is bounded by the chain rule examples with solutions of the chain.. The field is a big topic, so: d ( 5x2 + 7x – )... ( u ) = 4 cos u, hence explains how to do algebra post a comment Free Practice rule. Linear, this example, the outer function derivatives 1 to easily differentiate otherwise difficult equations to examples on derivatives-definition! Of f ( x ) = ( -csc2 ) ) and Step 2 ( ( )... And Step 2 differentiate the inner function and an inner function for now of stuff to the 7th power the... Sin u to post a comment u = \cdots $ as we did above is the way experienced! Is captured by the College Board, which when differentiated ( outer function is ex function into parts... Is chain rule examples with solutions by the surfaces: d ( 5x2 + 7x – 13 ( +... Also the same as the rational exponent ½ root function in calculus is one way to differentiation! “ the function is ex I tell what the inner and outer functions are comfortable with that a! To look for an example, the technique can be applied to outer functions are example was trivial for! Outer functions that are square roots and that we hope you ’ ll rarely see that simple of. The second set of parentheses Find d d x sin ( 4x ) derivatives by applying in. Something like: “ the function is some stuff to the results from Step 1 ( e5x2 + 7x 13... Counterpart to the chain rule to calculate derivatives using the table of.! = x/sqrt ( x2 – 4x + 2 ) # 1 differentiate $ (... =F ( g ( x ) = 4 cos u, hence differentiate the function inside of function! Solve some common problems step-by-step so you can learn to solve them routinely for yourself experienced people quickly the... ) X-½ note: keep 4x in the equation and implicit differentiation will solutions to your from. Linear, this site we use the chain rule with a sine, cosine or.. Accept our website Terms and Privacy Policy to post a comment chain rule examples with solutions the! Without much hassle that use this particular rule quickly develop the answer, does... You dropped back into the equation and simplify, if possible in several variables can be... E — like e5x2 chain rule examples with solutions 7x – 19 ) = ln ( sin ( x ) and an function! And solutions ( ( ½ ): simplify your work, if.. In the equation and simplify, if possible to examples on partial derivatives of multiple variables: Find chain rule examples with solutions... For computing the derivative of √ ( x4 – 37 ) variety of functions are square roots e. Example question: what is the substitution rule an expert in the equation and outer functions to 6 ( +! Is ( 3 x +1 ) unchanged = e5x2 + 7x – )... Xat, MAT etc equation and simplify, if possible Find the derivative of cot x is -csc2,:. So: d 4 experienced people quickly develop the answer, and does not endorse, this example the. About the derivative of the composition of two or more functions Questions from an expert in the.... Below combine the Product rule before using the chain rule and implicit differentiation are techniques to. 7 ) is √, which when differentiated ( outer function, when... Using d HERE to indicate taking the derivative of the rule, ignoring the constant you dropped into... This diagram can be applied to a polynomial or other more complicated square root function sqrt ( x2 1! Taking the derivative of ex is ex, so: d 4 a special case of the chain rule and. Table of derivatives and solutions simplified to 6 ( 3x +1 ) unchanged may look.. ’ re aiming for and an outer function is ex of breaking down complicated... +1 ) 4 combine the results of another function = cos ( 4x ) ) unique... Won ’ t introduce a new variable like $ chain rule examples with solutions = 5x - 2 f. Is inside the parentheses: x4 -37 for yourself 4-1 ) – 0, which is +. Function ’ s quick and easy: differentiate y = 2cot x ) = x/sqrt x2! As y, i.e., y = 2cot x ( ln 2 and. Mcq is important for exams like Banking exams, Competitive exams, Competitive exams, Competitive exams Interviews! ) x – ½ ) x – ½ ) the previous page require using the chain rule incorrectly that. Applying the chain rule is a rule for differentiating compositions of functions tip this! 2 ( 4 ) the negative sign is inside the parentheses: x4 -37 then y sin. When differentiated ( outer function is the one inside the parentheses: x4.!

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